- 吐吐很快乐
二分模板
- 2025-7-2 14:48:03 @
int bin_search(int *a, int n, int x){ //a[0]~a[n-1]是单调递增的
int left = 0, right = n; //注意:不是 n-1
while (left < right) {
int mid = left + (right-left)/2;
//int mid = (left + right) >> 1;
if (a[mid] >= x) right = mid;
else left = mid + 1;
} //终止于left = right
return left; //特殊情况:a[n-1] < x时,返回n
}
0 条评论
目前还没有评论...