1 条题解
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0
#include <iostream> using namespace std; int a[105][105],h,k=1,l,hy=0; int main(){ int n; cin >> n; hy = n-1; for(int i = 1;i<=n;i++) { h = n-hy; l = 1; for (; h != 0;) { a[h][l] = k++; h--; l++; } hy--; } for (int i = 1; i <= n; i++) { for (int j = 1; j <= n; j++) { if (a[i][j] == 0){ continue; }else { printf("%d ", a[i][j]); } } cout << "\n"; } }
(this is 博客on 白的码)
- 1
信息
- ID
- 298
- 时间
- 1000ms
- 内存
- 64MiB
- 难度
- 10
- 标签
- 递交数
- 6
- 已通过
- 2
- 上传者